تمارين - 2BACSEF

التانية باكالوريا العلوم التجريبية – خيار فرنسي


درس : Nombres Complexes 1

Exercice 5

Calculer le module de z dans les cas suivants:

a=3+i   ;;   b=23ia=3+i ~~~;; ~~~ b=\sqrt{2}-3i
c=1+2i13i   et   d=(1+2i)3c=\dfrac{1+\sqrt{2}i}{1-3i} ~~~ et ~~~ d=(1+2i)^3

a=3+i=32+12=9+1=10\begin{aligned} \quad \bullet\quad |a|&=|3+i|=\sqrt{3^2+1^2}\\&=\sqrt{9+1}=\sqrt{10} \end{aligned}

b=23i=22+(3)2=11\begin{aligned} \quad \bullet\quad |b|&=|\sqrt{2}-3i |\\&=\sqrt{\sqrt{2}^2+(-3)^2}=\sqrt{11} \end{aligned}

c=1+2i13i=1+2i13i=12+2212+(3)2=3010\begin{aligned} \quad \bullet\quad |c|&=\left|\dfrac{1+\sqrt{2}i}{1-3i}\right|=\dfrac{|1+\sqrt{2}i|}{|1-3i|} \\&=\dfrac{\sqrt{1^2+\sqrt{2}^2}}{\sqrt{1^2+(-3)^2}}=\dfrac{\sqrt{30}}{10} \end{aligned}

d=(1+2i)3=1+2i3=12+223=53=55\begin{aligned} \quad \bullet\quad |d| &=|(1+2i)^3|=|1+2i|^3 \\&=\sqrt{1^2+2^2}^3\\&=\sqrt{5}^3=5\sqrt{5} \end{aligned}